Question

शेरू खान6386976848ऑनलाइन करना है ​

Answer 1

Answer:

We are given that the graph of a linear equation in x and y passes through A (-1, -1) and B (2, 5).

We have to find the line equation using y−y1=y2−y1x2−x1(x−x1)

The line equation is

y−y1=y2−y1x2−x1(x−x1)y−(−1)=5−(−1)2−(−1)(x−(−1))y+1=5+12+1(x+1)y+1=2(x+1)y+1=2x+2y=2x+1

Therefore, the line equation is y=2x+1

We have to find the value of h in (h, 4). The line also passes through (h, 4)

y=2x+14=2h+12h=3h=32

We have to find the value of k in (12,k) . The line passes through (12,k)

y=2x+1k=2(12)+1k=1+1k=2

The value of h is 3/2 and the value of k is 2.

Answer 2

Explanation:

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