श्रेणी 1+2+3+....के कितने पदों का योगफल 5050 होगा?
Answers
Answered by
1
Answer:
900 is the ans of your question
Answered by
0
Answer:
100
Explanation:
यहां a=1
d=1
Sn=n/2{2a+(n-1)d}
5050=n/2{2.1+(n-1).1}
5050×2=n{n+1}
10100=n^2+n
n^2+n-10100=0
n^2+101n-100n-10100=0
(n+101)(n-100)=0
n=-101 (नगण्य या ऋणात्मक संख्या)
n=100
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