Question

shahrukh while riding a bicycle applies brakes such that the velocity reduces to 4m/s from 6m/s in 2 sec. calculate the acceleration?​

Answer 1

Answer:

• The Acceleration (a) of bicycle is - 1 m/s²

Given:

1. Initial velocity (u) = 6 m/s
2. Final velocity (v) = 4 m/s
3. Time period (t) = 2 sec.

Explanation:

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Acceleration:

Acceleration is defined as the rate of change of velocity.

Units:

• S.I units = m/s²
• C.G.S Units = cm/s²

Dimensional Formula:

• L T⁻²

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From the formula we know,

⇒ a = ( v - u ) / t

Here,

• a Denotes acceleration.
• v Denotes Final velocity
• u Denotes Initial velocity.
• t Denotes time taken.

Substituting the values,

⇒ a = ( 4 - 6 ) / 2

⇒ a = - 2 / 2

⇒ a = - 1

⇒ a = -1 m/s²

∴ The Acceleration (a) of bicycle is - 1 m/s².

Note:

• Negative sign denotes that bicycle is going under retardation.

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Answer 2

Given :

• Initial Velocity (u) = 6 m/s

• Final Velocity (v) = 4 m/s

• Time taken (t) = 2 seconds

To Find :

• Acceleration Produced

Solution :

We know that :

$\bigstar \: \boxed{ \sf \: Acceleration = \dfrac{Change \: in \: Velocity}{Time \: taken}}$

$\rightarrow \boxed{ \sf \: Acceleration = \frac{Final \: Velocity - Initial \: Velocity}{Time \: taken \: } }$

$\bigstar \: \: \large \boxed{ \red{ \sf \: a = \frac{v - u}{t}} }$

Here,

• a = Acceleration

• v = Final Velocity

• u = Initial Velocity

• t = Time taken

$\longrightarrow \sf \: a = \dfrac{4 - 6}{2}$

$\longrightarrow \sf \: a = \cancel \dfrac{ - 2}{2}$

$\longrightarrow \red{\sf \: a = - 1 \: m {s}^{ - 1} }$

$\therefore$ Acceleration Produced is -1 m/s².