Shalini has to cut out circles of diameter 1 1/4 cm from an aluminium strip of dimensions 8 3/4 cm by 1 1/4 cm. How many full circles can Shalini cut? Also calculate the wastage of the aluminium strip.
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diameter of circles= 11/4
length of strip = 83/4
now, no. of circles = 7 ans.
so , remaining length = 6/4. = 3/2
hence , remaining area =
495/32 or = 15.468 cm ² ans.
so , area wasted = 15.468
length of strip = 83/4
now, no. of circles = 7 ans.
so , remaining length = 6/4. = 3/2
hence , remaining area =
495/32 or = 15.468 cm ² ans.
so , area wasted = 15.468
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The answer is given below :
Diameter of a circle,
d = 1 1/4 cm = 5/4 cm
So, radius of each circle,
r = 5/8 cm
Area of each circle,
= π × r²
= π × (5/8)² cm²
= 25π/64 cm²
Now, area of the aluminium strip
= 8 3/4 × 1 1/4 cm²
= 35/4 × 5/4 cm²
= 175/16 cm²
The diameter of the circle = breadth of the strip
So, number of full circles
= length of the strip / diameter of a circle
= (8 3/4) / (1 1/4)
= (35/4) / (5/4)
= 7 [Ans.]
So, area of the seven circles
= 7 × 25π/64 cm²
= 275/32 cm² (put π = 22/7)
So, area wasted
= area of the strip - area of the seven circles
= (175/16 - 275/32) cm²
= 75/32 cm²
= 2.34375 cm² [Ans.]
Thank you for your question.
Diameter of a circle,
d = 1 1/4 cm = 5/4 cm
So, radius of each circle,
r = 5/8 cm
Area of each circle,
= π × r²
= π × (5/8)² cm²
= 25π/64 cm²
Now, area of the aluminium strip
= 8 3/4 × 1 1/4 cm²
= 35/4 × 5/4 cm²
= 175/16 cm²
The diameter of the circle = breadth of the strip
So, number of full circles
= length of the strip / diameter of a circle
= (8 3/4) / (1 1/4)
= (35/4) / (5/4)
= 7 [Ans.]
So, area of the seven circles
= 7 × 25π/64 cm²
= 275/32 cm² (put π = 22/7)
So, area wasted
= area of the strip - area of the seven circles
= (175/16 - 275/32) cm²
= 75/32 cm²
= 2.34375 cm² [Ans.]
Thank you for your question.
2842:
Thanks for your answer
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