Question

Shalini was 3 times as old as her son 2 years ago. 2yrs hence, twice of her age will be equal to 5 times that of her son's age. Find the present ages.

Answer 1

Answer:

here is yr ANSWER mate......

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

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$\green{\underline \bold{Given :}}$

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• 2 yrs ago Shalini was 3 times as old as her son.

• 2 yrs hence twice of her age will be equal to 5 times her son's age.

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$\red{\underline \bold{To \: Find:}}$

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• Present ages of both.

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$\large{\orange{\underline{\tt{Solution :-}}}}$

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Let the present age of shalini be 'x'

Let the present age of her son be 'y'

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$\underline{\bold{\texttt{2 yrs ago ages were:}}}$

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• Shalini = x - 2

• Son = y - 2

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$\purple{\underline \bold{According \: to \: the \ question :}}$

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$\sf \longmapsto x - 2 = 3(y - 2)$

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$\sf \longmapsto x - 2 = 3y - 6$

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$\sf \longmapsto x - 3y = -4$ --------(1)

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$\underline{\bold{\texttt{2 yrs hence ages will be:}}}$

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• Shalini = x + 2

• Son = y + 2

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$\purple{\underline \bold{According \: to \: the \ question :}}$

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$\sf \longmapsto 2(x + 2) = 5(y + 2)$

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$\sf \longmapsto 2x + 4 = 5y + 10$

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$\sf \longmapsto 2x - 5y = 6$ ------(2)

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$\underline{\bold{\texttt{Multiplying equation (1) by 2 }}}$

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$\sf \longmapsto 2x - 6y = -8$ -------(3)

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$\underline{\bold{\texttt{Subtracting (2) from (3)}}}$

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$\sf \longmapsto -y = -14$

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$\sf \longmapsto y = 14$

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$\underline{\bold{\texttt{Putting y = 14 in (1)}}}$

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$\sf \longmapsto x - 3(14) = -4$

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$\sf \longmapsto x - 42 = -4$

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$\sf \longmapsto x = 38$

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Hence Shalini is 38 yrs old and her son is 14 yrs old.

$\rule{200}5$