Shalini was three as old as her son 2 years ago. Two years hence, twise of her age will be equal to five times that of her son's age. Find their present ages.
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Answer:
let the age of son = x
age of sahil = y
2 years ago,
y-2 = 3(x-2)
y-2 = 3x-6
y = 3x-4 -----------(1)
after 2 years,
2(y+2) = 5(x+2)
2y + 4 = 5x + 10
2y = 5x + 6 ----------(2)
solving 1 and 2
2 (3x-4) = 5x + 6
6x - 8 = 5x + 6
x = 14
y = 3x - 4 = 3(14) - 4 = 42 - 4 = 38
present ages of father son duo is 38 of father and 14 of son
Step-by-step explanation:
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