Question

Shalini was three times as old as her son two years ago. Two years hence, twice of her age will be equal to five times that of her son's age. Find their present ages

Answer 1

Answer:

let the age of son = x

age of sahil = y

2 years ago,

y-2 = 3(x-2)

y-2 = 3x-6

y = 3x-4 -----------(1)

after 2 years,

2(y+2) = 5(x+2)

2y + 4 = 5x + 10

2y = 5x + 6 ----------(2)

solving 1 and 2

2 (3x-4) = 5x + 6

6x - 8 = 5x + 6

x = 14

y = 3x - 4 = 3(14) - 4 = 42 - 4 = 38

present ages of father son duo is 38 of father and 14 of son

Answer 2

Answer:

mark as brainlist answer

Step-by-step explanation:

let the age of son = x

age of sahil = y

2 years ago,

y-2 = 3(x-2)

y-2 = 3x-6

y = 3x-4 -----------(1)

after 2 years,

2(y+2) = 5(x+2)

2y + 4 = 5x + 10

2y = 5x + 6 ----------(2)

solving 1 and 2

2 (3x-4) = 5x + 6

6x - 8 = 5x + 6

x = 14

y = 3x - 4 = 3(14) - 4 = 42 - 4 = 38

present ages of father son duo is 38 of father and 14 of son