Question

Shalini was three times as old as her son two years ago.Two years hence ,twice of her age will be equal to five times that of her son's age.Find there present ages?

Answer 1

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Vrushalikawalkar

18.06.2020

Math

Secondary School

+5 pts

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Shalini was 3 times as old as her son two years ago . 2 years hence ,twice of her age will be equal to 5 times that of her son's age . Find the present ages.

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Answers

lohithchittala

lohithchittala Ace

Answer:

Shalini's age is 38 years

Shalini's son's age is 14 years

Step-by-step explanation:

Let Shalini's age be 'x'

Let her son's age is 'y'

Two years ago

x-2=3(y-2)

x-2 = 3y-6

x=3y-4 .............(a)

Two years after

2(x+2)=5(y+2)

2x+4=5y+10

2x=5y+6..........(b)

Substitute (a) in (b)

2(3y-4) = 5y+6

6y-8=5y+6

y-14=0

y=14 substitute in (a)

x=3(14) -4 = 42-4 = 38

y=14

x=38

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