Shalini was three times as old as her son two years ago.Two years hence ,twice of her age will be equal to five times that of her son's age.Find there present ages?
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Vrushalikawalkar
18.06.2020
Math
Secondary School
+5 pts
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Shalini was 3 times as old as her son two years ago . 2 years hence ,twice of her age will be equal to 5 times that of her son's age . Find the present ages.
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lohithchittala
lohithchittala Ace
Answer:
Shalini's age is 38 years
Shalini's son's age is 14 years
Step-by-step explanation:
Let Shalini's age be 'x'
Let her son's age is 'y'
Two years ago
x-2=3(y-2)
x-2 = 3y-6
x=3y-4 .............(a)
Two years after
2(x+2)=5(y+2)
2x+4=5y+10
2x=5y+6..........(b)
Substitute (a) in (b)
2(3y-4) = 5y+6
6y-8=5y+6
y-14=0
y=14 substitute in (a)
x=3(14) -4 = 42-4 = 38
y=14
x=38
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