Shalini was three times as old as her son two years ago. Two years hence, twice of her age will be equal to five times that of her son's age. Find their present ages.
Pls give me an answer using one variable ... Correct and fully explained answer I'll mark as Brainiest answer...
Answers
Answered by
1
Answer:
shalini=38years , son=14 years
Step-by-step explanation:
let
two years ago
age of son be x and shalini be 3x
two years after present day
shalini=3x+4 ,. son=x+4
ATQ,
2(3x+4)=5(x+4)
6x+8. =5x+20
6x-5x. =20-8
x. =12
present age,
shalini=3x+2
=3×12+2
=36+2
=38years
his son=x+2
=12+2
= 14 years
Answered by
43
Given : Shalini was three times as old as her son two years ago & Two years hence, twice of her age will be equal to five times that of her son's age.
Need To Find : Shalini's and her Son's Present age ?
⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀
❍ Let's say , that the two years ago
- Shalini's son's age be x years & Shalini's age be 3x years i.e. Shalini was three times as old as her son.
- & Present age of Shalini and her son will be ( 3x + 2 ) years and ( x + 2 ) years , respectively.
⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀☆ Two years hence , their ages :
- Shalini's age will be = ( 3x + 4 ) years &
- Shalini Son's age will be = ( x + 4 ) years .
- Two years hence, twice of her [ Shalini ] age will be equal to five times that of her son's age.
Therefore,
- Present age of Shalini is , ( 3x + 2 ) = ( 3(12) + 2 ) = 38 years &
- Present age of her son is , ( x + 2 ) = ( 12 + 2 ) = 14 years .
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