Question

shally buys some chocolates at the rate of ₹10 per chocolate. she also buys an equal number of candies at the rate ₹5 per candy. she make 20% profit on chocolate and 8% profit on candies. at the end of day, all chocolates and candies are sold out and her profit is ₹240. the number of chocolates she had purchased is

1)100
2)90
3)150
4)200​

Answer 1

Step-by-step explanation:

let total chocolate brought be=n

cost of all chocolates=10n

therefore,cost of candies=5n

profit made on chocolates =20%

SP of chocolates=10n+(20×10n÷100)

=10n+2n

=12n Rupees

cost of candies=5n

profit on candies=8%

SP of candies =5n+(8×5n ÷100)

=5n+0.4n

=5.4n Rupees

ATQ, her profit at the end of the day=240

profit on chocolates +profit on candies=240

2.4n=240

n=100

therefore she brought 100 candies and chocolates in the start of the day

Answer 2

$\rm\dag\large\underline{ Solution: }$

Let shally purchased X chocolates.

Then, the the total cost of chocolates =₹ 10x

Similarly, she purchased X candies .

Then, the total cost of candies = ₹ 5x

According to the question,

$\rm\small Profit \: on \: chocolates = 20\% \: of \: 10x \\ = \frac{20}{100} \times 10x \\ = ₹ \: 2x$

$\rm\small Profit \: on \: candies = 8\% \: of \: 5x \\ = \frac{8}{100} \times 5x \\ = ₹ \: 0. 4x</p><p>$

$\rm Total\: Profit = 2x \: + \: 0.4x \\ = ₹ 2.4x$

Again, according to the question

$2.4x = 240 \\ \rm\Rightarrow x= \frac{240}{2.4} \\ = 100$

Therefore, she purchased 100 chocolates.