Question

Shalu drives 12 km to the East and then 16 km to the South to reach the river. Had she taken the shortest rout to the river, how far would she have driven?

Note: Solve by the Pythagoras Theorem and also draw a rough sketch

Answer 1

Step-by-step explanation:

Here, perpendicular is missing. Let it be x.

$\tt{ \longmapsto \: {p}^{2} + {b}^{2} = {h}^{2} }$

$\tt{ \longmapsto \: {x}^{2} + {12}^{2} = {16}^{2} }$

$\tt{ \longmapsto \: {x}^{2} + 144 = 256 }$

$\tt{ \longmapsto \: {x}^{2} = 256 - 144}$

$\tt{ \longmapsto \: {x}^{2} = 112 }$

$\tt{ \longmapsto \: x = \sqrt{112} }$

$\tt{ \longmapsto \:x = 11 }$

Therefore, Shalu is 11 km away from the starting point.