shan Sweets Scall was placing an order for making and pain
sweets. Two sizes of boxes were required. The
overlaps 5% of the total surfaces in
es for 1000 cm find the cost of cardboard required for
25 cm x 20 cm x 5cm and the smaller of dimens
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Shanti sweets stall was placing an order for making cardboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of dimensions 25 cm ×20 cm ×5 cm and the smaller of dimensions 15 cm ×12 cm ×5 cm. For all the overlaps, 5%of the total surface area is required extra. If the cost of the cardboard is 4 for 1000 cm
2
, find the cost of cardboard required for supplying 250 boxes of each kind.
HARD
VIDEO EXPLANATION
ANSWER
Total S.A of bigger box
=2(lb+bh+lh)
=2(25×20+25×5+20×5) cm
2
=2(500+125+100)
=1450 cm
2
⇒For overlapping extra area required =
100
450×5
=72.5 cm
2
∴ Total S.A (including overlaps)
=1450+72.5=1522.5 cm
2
Area of cardboard sheet for 250 such boxes
=(1522.5×250) cm
2
Total S.A of smaller box
=2(15×12+15×5+12×5)cm
2
=630 cm
2
For overlapping area required =
100
630×5
=31.5 cm
2
Total S.A (including overlaps)=630+31.5=661.5 cm
2
Area of cardboard sheet required for 250 such boxes
=250×661.5cm
2
=165375 cm
2
Total cardboard sheet required =380625+165375
=54000 cm
2
⇒Cost of 1000 cm
2
cardboard sheet = Rs.4
⇒Cost of 546000 cm
2
cardboard sheet
= Rs.
1000
546000×4
= Rs. 2184
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