Math, asked by PorterGregory780, 1 month ago

Shania is making a scale diagram of the badminton court at the community center. She uses a scale of 1 centimeter to 0.5 meter to draw the scale diagram. If the scale length of the badminton court is 26.8 centimeters and the scale width is 12.2 centimeters, what is the actual area of the court?
A.
1,307.84 square meters
B.
326.96 square meters
C.
81.74 square meters
D.
78 square meters

Answers

Answered by margacisc
1

Answer:

81.74 m²

Step-by-step explanation:

1m = 100cm

1cm → 0.5m

1cm → 0.5 · 100cm = 50cm

The scale:

length = 26.8cm · 50 = 1,340cm = 13.40m

width = 12.2cm · 50 = 610cm = 6.10m

The area of the court:

A = 13.40 · 6.10 = 81.74 m²

Answered by amitnrw
2

Given : Shania is making a scale diagram of the badminton court at the community center.  

She uses a scale of 1 centimeter to 0.5 meter to draw the scale diagram.

scale length of the badminton court is 26.8 centimeters and the scale width is 12.2 centimeters,

To Find : Actual area of the court

A.  1,307.84 square meters

B.  326.96 square meters

C.  81.74 square meters

D.   78 square meters

Solution:

scale of 1 centimeter to 0.5 meter

Length = 26.8 cm

=> actual length = 26.8 x 0.5  m

= 13.4  m

width  = 12.2 cm

=> actual width  = 12.2 x 0.5  m

=6.1  m

Area = length x width

= 13.4 x 6.1

= 81.74  m²

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