Shankar takes a loan of 10000 at a Compound interest rate of 10%per annum Find the difference between the Compound interest and the simple interest at the same rate for 2year.
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Answered by
42
Heya user
Here is your answer !!
Principal = Rs 10000
Rate = 10%
Time = 2 yrs .
So, Compound Interest = P(1+R/100)² - P
= Rs. 10000(1+10/100)² - 10000
= Rs. 10000(11/10)² - 10000
= Rs. 10000*121/100 - 10000
= Rs. 12100 - 10000
= Rs. 2100 .
Simple Interest = P*R*T /100
= Rs. 10000*10*2/100
= Rs. 2000
So , difference between the Compound interest and the simple interest = Rs. 2100 - Rs. 2000 = Rs. 100 (Ans)
Hope it helps !!
Here is your answer !!
Principal = Rs 10000
Rate = 10%
Time = 2 yrs .
So, Compound Interest = P(1+R/100)² - P
= Rs. 10000(1+10/100)² - 10000
= Rs. 10000(11/10)² - 10000
= Rs. 10000*121/100 - 10000
= Rs. 12100 - 10000
= Rs. 2100 .
Simple Interest = P*R*T /100
= Rs. 10000*10*2/100
= Rs. 2000
So , difference between the Compound interest and the simple interest = Rs. 2100 - Rs. 2000 = Rs. 100 (Ans)
Hope it helps !!
Answered by
10
CI=rs 2100
SI=RS 2000
Difference = ci-si
2100-2000=100
ans=rs100
SI=RS 2000
Difference = ci-si
2100-2000=100
ans=rs100
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