Math, asked by sumitkumar8267738, 2 months ago

Shanta Bai is three times as old as her son. After twelve years her age will be twice as that of her son. Find their present ages.​

Answers

Answered by Anonymous
33

Answer :-

  • Shanta Bai's age = 36 and her son's age = 12.

To Find :-

  • The present age of Shanta Bai and her son.

Given :-

  • Shanta Bai is three times as old as her son. After twelve years her age will be twice as that of her son.

Step By Step Explanation :-

Let us consider the present age of Shanta Bai's son be x. Then Shanta Bai's age will be 3x.

After 12 years

Shanta Bai's son's age will be x + 12. Shanta Bai's age will be 3x + 12 and will be twice as that as of her son.

So equation will be ⤵

  \bigstar\sf{ \boxed{ \boxed{\purple{2(x + 12) = 3x + 12}}}}

So let's solve the equation !!

 \implies \sf2(x + 12) = 3x + 12 \\  \\\implies \sf2x + 24 = 3x + 12 \\ \\\implies \sf 24 - 12 = 3x - 2x \\  \\ \implies \sf12 = x

Therefore x = 12

Hence age of Shanta Bai = 3x => 36 and her son's age => 12

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