Shanti baked 5p croissant Jon baked twice as many croissant as shanti Ching baked 16 fewer croissant Han Jon find the total number of croissant they baked in terms of P
Answers
Answered by
1
Shanti=5
jon=5×2=10
Ching=jon+16
=10+16
=26
total no of croissant=5+10+26
=41p
hope this helps you
jon=5×2=10
Ching=jon+16
=10+16
=26
total no of croissant=5+10+26
=41p
hope this helps you
Golda:
Wrong answer.
Answered by
2
Solution :-
Shanti baked croissants = 5p
Jon baked twice as many croissants as Shanti baked = 2*(5p)
Ching baked 16 croissants less than Jon = 2*(5p) - 16
Total number of croissants = 5p + 2*(5p) + 2*(5p) - 16
⇒ 5p + 10p + 10p - 16
⇒ (25p - 16) croissants
The total number of croissants they baked in term of p are (25p - 16).
Answer.
Shanti baked croissants = 5p
Jon baked twice as many croissants as Shanti baked = 2*(5p)
Ching baked 16 croissants less than Jon = 2*(5p) - 16
Total number of croissants = 5p + 2*(5p) + 2*(5p) - 16
⇒ 5p + 10p + 10p - 16
⇒ (25p - 16) croissants
The total number of croissants they baked in term of p are (25p - 16).
Answer.
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