Shanti Sweet's Stall was placing an order for making cardboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of Dimensions 25cm *20cm *5cm and the smaller of dimensions 15 cm 12 cm 5 cm. For all theoverlaps , 5% of the total surface area is required extra. If the cost of the cardboard is Rs4 for 1000 cm². find the cost of cardboard required for Supplying 250 boxes of Each kind.
Answers
2184 Rs is the cost of cardboard required for Supplying 250 boxes of Each kind. for Rs4 for 1000 cm² , Dimensions 25cm *20cm *5cm & 15 cm 12 cm 5 cm.
Step-by-step explanation:
The bigger of Dimensions 25cm *20cm *5cm
Surface Area = 2 * (25 * 20 + 25 * 5 + 20*5)
= 2 (500 + 125 + 100)
= 2 * 725
= 1450
smaller of dimensions 15 cm 12 cm 5 cm.
Surface Area = 2 * ( 15*12 + 15*5 + 12*5)
= 2 ( 180 + 75 + 60)
= 2 * 315
= 630
Total Surface Area = 1450 + 630 = 2080 cm²
For all the overlaps , 5% of the total surface area is required extra
= (5/100)2080 = 104 cm²
Surface Area required for one of Bigger + one Smaller = 2080 + 104
= 2184 cm²
cost for 1000 cm² = 4
cost for 2184 cm² ( 1 box of Small & Large) = 4 * 2184 /1000
Cost for 250 boxes of Each kind = 250 * 4 * 2184 /1000
= 2184 Rs
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Answer:
Step-by-step explanation:
Area of smaller box and bigger box ={2{lh+bh+lb}+2{lh+bh+lh}}
={2{125+100+500}+2{75+60+180}
={1450+630}
=2080cm²
Area extra cardboard box
=TSA of cardboard * 5%
=2080*5%
=2080*5\100
=104cm³
Total area of cardboard required
=TSA + extra cardboard
=2080+104
=2184cm²
Area of cardboard for 250 boxes
= Area of one box*250
=2184*250
=546000²
Cost of 1000cm²of cardboard=4rupee
Cost of cardboard of 546000cm2
=546*4
=Rupee 2184