Math, asked by umaralishihab1, 1 year ago

Shanti Sweets Stall was placing an order for making cardboard boxes for packing
their sweets. Two sizes of boxes were required. The bigger of dimensions
25 cm x 20 cm x 5 cm and the smaller of dimensions 15 cm x 12 cm x 5 cm. For all the
overlaps, 5% of the total surface area is required extra. If the cost of the cardboard is
4 for 1000 cm”, find the cost of cardboard required for supplying 250 boxes of each
kind.​

it's final answer is ₹2184 but I don't know the method plzzz help

Answers

Answered by Diya528
3

Answer:

Answer is Rs.2184

Step-by-step explanation:

Total Surface area of bigger box=

2(25*20+20*5+25*5)

=2(500+100+125)

=2*725

=1450cm2

TSA of smaller box=2(15*12+12*5+15*5)

=2*315 =630cm2

Total area of both boxes=1450+630 =2080cm2

5% of 2080cm2= 104cm2

5% extra was required for folding..

Including 5% total area = 2184 cm2

Area of 250 boxes =2184*250=546000cm2

1000cm2=Rs.4

546000 cm2=x

=x=4/1000*546000

=x=Rs.2184 (Ans)

Similar questions