Shanti Sweets Stall was placing an order for making cardboard boxes for packing
their sweets. Two sizes of boxes were required. The bigger of dimensions
25 cm x 20 cm x 5 cm and the smaller of dimensions 15 cm x 12 cm x 5 cm. For all the
overlaps, 5% of the total surface area is required extra. If the cost of the cardboard is
4 for 1000 cm², find the cost of cardboard required for supplying 250 boxes of each
kind.
Answers
✩☞ the cost of cardboard required for supplying 250 boxes of each kind is : Rs. 2184 ✔
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Length (l) = 25 cm,
Breadth (b) = 20 cm,
Height (h) = 5 cm
Now,
✩☞ Total surface area of a box = 2(lb + bh + hl)
= 2[(25 x 20) + (20 x 5) + (5 x t25)] cm2
- = 2 [500 + 100 + 125] cm2
- = 2[725] cm2
- = 1450 cm2
Therefore,
total surface area of 250 boxes = (250 x 1450) cm2 = 362500 cm2
Length (l) = 15 cm,
Breadth (b) = 12 cm,
Height (h) = 5 cm
✩☞ Total surface area of a box =
2 [lb + bh + hl]
= 2[(15 x 12) + (12 x 5) + (5 x 15)] cm2
- = 2[180 + 60 + 75] cm2
- = 2[315] cm2 = 630 cm2
∴ Total surface area of 250 boxes = (250 x 630) cm2 = 157500 cm2
Now,
total surface area of both type of boxes
- = 362500 cm2 +157500 cm2
- = 520000 cm2
⟹ Area for overlaps = 5% of [total surface area]
- = (5/100) x 520000 cm2
- = 26000 cm2
∴ Total surface area of the cardboard required = [Total surface area of 250 boxes of each type] + [Area for overlaps]
- = 520000 cm2 + 26000 cm2
- = 546000 cm2
∵ Cost of 1000 cm2 cardboard = Rs. 4
∴ Cost of 546000 cm2 cardboard
- = Rs.(4×546000)/1000 = Rs. 2184
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☘彡✩Thank You For Asking✩彡☘
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