Math, asked by samarthsaxena1220, 5 months ago

Shanti Sweets Stall was placing an order for making cardboard boxes for packing
their sweets. Two sizes of boxes were required. The bigger of dimensions
25 cm x 20 cm x 5 cm and the smaller of dimensions 15 cm x 12 cm x 5 cm. For all the
overlaps, 5% of the total surface area is required extra. If the cost of the cardboard is
4 for 1000 cm², find the cost of cardboard required for supplying 250 boxes of each
kind.

Answers

Answered by pratyush15899
46

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✩☞ the cost of cardboard required for supplying 250 boxes of each kind is : Rs. 2184

__________________________________

\Large\bf\underline{\red{E}\green{X}\orange{P}\pink{L}\red{A}\purple{N}\orange{A}\blue{T}\red{I}\purple{O}N}

  { \fbox {\red{For \:  bigger \:  box :}}}

\underline \mathbf{ \purple{Given: }}

Length (l) = 25 cm,

Breadth (b) = 20 cm,

Height (h) = 5 cm

Now,

✩☞ Total surface area of a box = 2(lb + bh + hl)

= 2[(25 x 20) + (20 x 5) + (5 x t25)] cm2

  • = 2 [500 + 100 + 125] cm2
  • = 2[725] cm2
  • = 1450 cm2

Therefore,

total surface area of 250 boxes = (250 x 1450) cm2  = 362500 cm2

 \fbox \red{For smaller box:}

\underline \mathbf{ \purple{Given: }}

Length (l) = 15 cm,

Breadth (b) = 12 cm,

Height (h) = 5 cm

✩☞ Total surface area of a box =

2 [lb + bh + hl]

= 2[(15 x 12) + (12 x 5) + (5 x 15)] cm2

  • = 2[180 + 60 + 75] cm2 
  • = 2[315] cm2 = 630 cm2

Total surface area of 250 boxes = (250 x 630) cm2 = 157500 cm2

Now,

total surface area of both type of boxes

  • = 362500 cm2 +157500 cm2
  •  = 520000 cm2

 Area for overlaps = 5% of [total surface area]

  • = (5/100) x 520000 cm2 
  • = 26000 cm2

∴ Total surface area of the cardboard required = [Total surface area of 250 boxes of each type] + [Area for overlaps]

  • = 520000 cm2 + 26000 cm2 
  • = 546000 cm2

∵ Cost of 1000 cm2 cardboard = Rs. 4

∴ Cost of 546000 cm2 cardboard

  • = Rs.(4×546000)/1000 = Rs. 2184

★━━━✩━━★♥️♥️★━━✩━━━★

Thank You For Asking

↬↬↬ \small{\fcolorbox{grey}{yellow}{Hope \ it \ helps}}

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