Question

Shanti Sweets Stall was placing an order for making cardboard boxes for packing
their sweets. Two sizes of boxes were required. The bigger of dimensions
25 cm x 20 cm x 5 cm and the smaller of dimensions 15 cm x 12 cm x 5 cm. For all the
24 for 1000 cm, find the cost of cardboard required for supplying 250 boxes of each
overlaps, 5% of the total surface area is required extra. If the cost of the cardboard is
of tape is needed for all the 12 edges?
kind​

Answer 1

Step-by-step explanation:

Total S.A of bigger box

=2(lb+bh+lh)

=2(25×20+25×5+20×5) cm²

=2(500+125+100)

=1450 cm ²

⇒For overlapping extra area required =

100

450×5

=72.5 cm²

∴ Total S.A (including overlaps)

=1450+72.5=1522.5 cm ²

Area of cardboard sheet for 250 such boxes

=(1522.5×250) cm²

Total S.A of smaller box

=2(15×12+15×5+12×5)cm ²

=630 cm ²

For overlapping area required = 100

630×5

=31.5 cm ²

Total S.A (including overlaps)=630+31.5=661.5 cm²

Area of cardboard sheet required for 250 such boxes

=250×661.5cm ²

=165375 cm²

Total cardboard sheet required =380625+165375

=54000 cm ²

⇒Cost of 1000 cm ²cardboard sheet = Rs.4

⇒Cost of 546000 cm²cardboard sheet = Rs.546000×4÷1000

= Rs. 2184

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