Shanti Sweets Stall was placing an order for making cardboard boxes for packing
their sweets. Two sizes of boxes were required. The bigger of dimensions
25 cm x 20 cm x 5 cm and the smaller of dimensions 15 cm x 12 cm x 5 cm. For all the
overlaps, 5% of the total surface area is required extra. If the cost of the cardboard is
4 for 1000 cm?, find the cost of cardboard required for supplying 250 boxes of each
kind.
Answers
Answer:
Total S.A of bigger box
=2(lb+bh+lh)
=2(25×20+25×5+20×5) cm
2
=2(500+125+100)
=1450 cm
2
⇒For overlapping extra area required =
100
450×5
=72.5 cm
2
∴ Total S.A (including overlaps)
=1450+72.5=1522.5 cm
2
Area of cardboard sheet for 250 such boxes
=(1522.5×250) cm
2
Total S.A of smaller box
=2(15×12+15×5+12×5)cm
2
=630 cm
2
For overlapping area required =
100
630×5
=31.5 cm
2
Total S.A (including overlaps)=630+31.5=661.5 cm
2
Area of cardboard sheet required for 250 such boxes
=250×661.5cm
2
=165375 cm
2
Total cardboard sheet required =380625+165375
=54000 cm
2
⇒Cost of 1000 cm
2
cardboard sheet = Rs.4
⇒Cost of 546000 cm
2
cardboard sheet
= Rs.
1000
546000×4
= Rs. 2184
Answer:
bigger box t.s.a=2(lb+bh+hl)
2(25×20+20×5+5×25)
2(500+100+125)
2(725)
1450cm2
5%overlap 1450×5/100
72.5
total area =1450+72.5
1522.5cm2
1 box =1522.5cm2
250 box =1522.5×250
380625
smaller box t.s.a =2(lb+bh+hl)
2(15×12+12×5+5×15)
2(180+60+75)
2(315)
630cm2
5%overlap =530×5/100
31.5cm2
total area =630+31.5
661.5cm2
1 box=661.5cm2
250 box=661.5×250
165375
total cardboard =380625+165375
546000cm2
total cost=546000×4/1000
2184rupees