Question

Shanti Sweets Stall was placing an order for making cardboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of dimensions 25 cm×20cm×5cm and the smaller of dimension 15cm×12cm×5cm. For all the overlaps, 5% of the total surface area is required extra. If the cost of the cardboard is Rs. 4 for 1000 cm2, find the cost of cardboard required for supplying 250 boxes of each kind.​

Answer 1

Answer:

₹2184

Step-by-step explanation:

Total S.A of bigger box

=2(lb+bh+lh)

=2(25×20+25×5+20×5) cm

2

=2(500+125+100)

=1450 cm

2

⇒For overlapping extra area required =

100

450×5

=72.5 cm

2

∴ Total S.A (including overlaps)

=1450+72.5=1522.5 cm

2

Area of cardboard sheet for 250 such boxes

=(1522.5×250) cm

2

Total S.A of smaller box

=2(15×12+15×5+12×5)cm

2

=630 cm

2

For overlapping area required =

100

630×5

=31.5 cm

2

Total S.A (including overlaps)=630+31.5=661.5 cm

2

Area of cardboard sheet required for 250 such boxes

=250×661.5cm

2

=165375 cm

2

Total cardboard sheet required =380625+165375

=54000 cm

2

⇒Cost of 1000 cm

2

cardboard sheet = Rs.4

⇒Cost of 546000 cm

2

cardboard sheet

= Rs.

1000

546000×4

= 2184

please mark as brainliest ❤️ i really need it

Answer 2

Let l, b and h be the length, breadth and height of the box.

★ In Bigger Box:

• l = 25 cm
• b = 20 cm
• h = 5 cm

$\sf$

$\sf \red{Total \: surface \: area \: of \: bigger \: box = 2(lb+lh+bh)}$

$\sf \longrightarrow \: [2(25×20+25×5+20×5)]$

$\sf \longrightarrow \: [2(500+125+100)]$

$\sf \longrightarrow 2 \times 725$

$\sf \longrightarrow 1450 \: {cm}^{2}$

$\sf$

★ In Smaller Box:

• l = 15 cm
• b = 12 cm
• h = 5 cm

$\sf$

$\sf \red{Total \: surface \: area \: of \: smaller \: box = 2(lb+lh+bh)}$

$\sf \longrightarrow \: [2(15×12+15×5+12×5)] \: {cm}^{2}$

$\sf \longrightarrow \: [2(180+75+60)] \: {cm}^{2}$

$\sf \longrightarrow 2 \times 315 \: {cm}^{2}$

$\sf \longrightarrow 630 \: {cm}^{2}$

$\sf$

★ Area of both cuboid

$\sf \longrightarrow 1450 + 630$

$\sf \longrightarrow 2080 \: {cm}^{2}$

$\sf$

★ Total area of cuboid

$\sf \longrightarrow 2080 + 5\% \: of \: 2080$

$\sf \longrightarrow 2080 + \frac{5}{100} \times 2080$

$\sf \longrightarrow 2080 + 104$

$\sf \longrightarrow 2184 \: {cm}^{2}$

$\sf$

Total area of 250 boxes = 250 × 2184

Cost of 1000 cm² in ₹4.

Cost of 1 cm² is ₹4/1000.

Cost of 250 × 2184 is ₹4/1000×250×2184 = ₹2184

$\sf$

Therefore, the cost of cardboard required for supplying 250 boxes of each kind will be Rs. 2184.