Shanti Sweets Stall was placing an order for making cardboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of dimensions 25 cm x 20 cm x 5 cm and the smaller of dimensions 15 cm x 12 cm x 5 cm. For all the overlaps, 5% of the total surface area is required extra. If the cost of the cardboard is 34 for 1000 cm, find the cost of cardboard required for supplying 250 boxers of each kind
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Step-by-step explanation:
Total S.A of bigger box
=2(lb+bh+lh)
=2(25×20+25×5+20×5) cm
2
=2(500+125+100)
=1450 cm
2
⇒For overlapping extra area required =
100
450×5
=72.5 cm
2
∴ Total S.A (including overlaps)
=1450+72.5=1522.5 cm
2
Area of cardboard sheet for 250 such boxes
=(1522.5×250) cm
2
Total S.A of smaller box
=2(15×12+15×5+12×5)cm
2
=630 cm
2
For overlapping area required =
100
630×5
=31.5 cm
2
Total S.A (including overlaps)=630+31.5=661.5 cm
2
Area of cardboard sheet required for 250 such boxes
=250×661.5cm
2
=165375 cm
2
Total cardboard sheet required =380625+165375
=54000 cm
2
⇒Cost of 1000 cm
2
cardboard sheet = Rs.4
⇒Cost of 546000 cm
2
cardboard sheet
= Rs.
1000
546000×4
= Rs. 2184
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