Math, asked by mohdaltafsheikh, 8 months ago

Shanti sweets stall was placing the order for making cardboard boxes for packing their sweets. Two sizes of boxes are required. The bigger of dimensions 25 cm× 20 cm× 5 cm and the smaller dimensions 15 cm× 12 cm×5cm.For all the overlaps, 5% of total surface area is required extra. If the cost of cardboard is rs 4 for 1000 cm square. Find the cost of cardboard required for supplying 250 boxes of each kind.​

Answers

Answered by silentlover45
9

Given:-

  • The bigger of dimensions 25 cm× 20 cm× 5 cm and the smaller dimensions 15 cm× 12 cm×5cm.
  • all the overlaps, 5% of total surface area is required extra.
  • the cost of cardboard is rs 4 for 1000 cm square.

To find:-

  • Find the cost of cardboard required for supplying 250 boxes of each kind.

Solutions:-

  • Length of bigger box = 25cm
  • Breadth of bigger box = 20cm
  • Height of bigger box = 5cm

Total surface area bigger box = 2(lb + bh + hl)

= 2(25 × 20 + 20 × 5 + 5 × 25)

= 2(500 + 100 + 125)

= 2 × 725

= 1450cm²

Extra area required for overlapping = 1450 × 5 / 100

= 1450/20

= 72.5cm²

While considering all overlaps total of 1 bigger box.

= 1450 + 72.5

= 1522.5cm²

Area of cardboard sheet required for 250 such bigger boxes.

= 1522.5 × 250

= 380625cm²

Total surface area of smaller box.

= 2(15 × 12 + 15 × 5 + 12 × 5)

= 2(180 + 75 + 60)

= 2 × 315

= 630

Therefore,

Extre area of required for overlapping.

= 630 × 5 / 100

= 63/2

= 31.5cm²

Total surface area of 1 smaller box while considering all overlaps.

= 630 + 31.5

= 661.5cm²

Area of cardboard sheet required for 250 smaller boxes.

= 250 × 661.5

= 165375cm²

Total cardboard sheet required = 380632 + 165375

= 546000cm²

Cost of 1000cm² cardboard sheet = Rs 4.

Cast of 546000cm² cardboard sheet.

= Rs (546000/1000 × 4)

= Rs 546 × 4

= Rs 2184

Hence, the cost of cardboard sheet required for 250 such boxes of each will be Rs 2184.

Answered by saanvigrover2007
2

 \pmb{ \sf{Question :}}

Shanti Sweets Stall was placing an order for making cardboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of dimensions 25 cm × 20 cm × 5 cm and the smaller of dimensions 15 cm × 12 cm × 5 cm. For all the overlaps, 5% of the total surface area is required extra. If the cost of the cardboard is Rs. 4 for 1000 cm², find the cost of cardboard required for supplying 300 boxes of each kind.

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\pmb{ \sf { Formula \: to \: be \: used: }}

:\mapsto{\small{\underline{\boxed{\sf{TSA \: of \: cuboid =2(lb +bh + hl)}}}}}

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\pmb{\sf{Solution : }}

 \red \bigstar\textsf{ \: For bigger box,} \\

\textsf{ l= 25 cm b = 20 cm h = 5 cm}

\textsf{Total surface area of the bigger box} \\  \textsf{= 2 (lb + bh + hl)} \\  \textsf{= 2[(25)(20) + (20)(5) + (5)(25)]} \\  \textsf{= 2(500 + 100 + 125) = 1450 cm²}

\sf{Cardboard \:  required \:  for \:  all \:  the  \: overlap }\\  \sf{ =  1450   \times \frac{5}{100}  = 72.5 \:  {cm}^{2} }

 \sf{\therefore Net \:  surface \:  area  \: of  \: the \:  bigger \:  box} \\   \sf{= 1450 cm² + 72.5 cm² = 1522.5 cm²}

\therefore \textsf {Net surface area of 250 bigger boxes} \\ \sf{= 1522.5  \times 250 = 380625 cm²}

 \sf{Cost \:  of  \: cardboard =  \frac{4}{1000} \times  38065 =  ₹1522.50} \\

\red \bigstar \textsf { \: For smaller box,}

 \textsf{I = 15 cm b = 12 cm h = 5 cm}

\textsf{Total surface area of the smaller box} \\\textsf{= 2 (lb + bh + hl)} \\\textsf{= 2[(15)(12) + (12)(5) + (5)( 15)] }\\\textsf{= 2[ 180 + 60 + 75] }\textsf{= 630cm²}

 \textsf{Cardboard required for all the overlaps} \\  \sf{ = 630 \times  \frac{5}{100} = 31.5 {cm}^{2}  }

\therefore \textsf{Net surface area of the smaller box} \\\sf{= 630 cm^2 + 31.5 cm^2 = 661.5 cm^2}

\therefore \textsf{Net surface area of 250 smaller boxes} \\ \sf{ = 661.5  \times 250 = 165375 cm^2}

 \sf{Cost \:  of \:  cardboard =  \frac{4}{1000}  \times 165375 = ₹661.50} \\

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 \pmb{\sf{Final \: Answer :}}

 \textsf{Total Cost =  ₹ 1522.50 + ₹661.50} \\   =   \boxed{ \underline{\large{\sf \pink{ ₹2184}} }}

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 \pmb{ \sf{Note :  }}

 \footnotesize \rm{  : \mapsto For \:  diagrams, \:  refer \:  to \:  the  \: attachment}

  \footnotesize \textrm{:↦ Do thanks and rate the answer if it was helpful}

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