Math, asked by gaminghrter, 17 days ago

Shanu and Pawan working alone can finish a piece of work in 10 days and 15 days respectively. If shanu and pawan work together, but shanu leaves the job after 2 days. How much of the work is left then? ​

Answers

Answered by ParikshitPulliwar
1

Answer: 10 days

Step-by-step explanation:

work done by Shanu in 1 day= 1/10

work done by pawan in 1 day= 1/15

now work done by both in one day = 1/10+1/15= 5/30 = 1/6

work done by both in 2 days = 1/6×2=1/3

now remain work = 1-1/3 = 2/3

now again time taken by pawan to do the work in one day 1/15

time taken by pawan to complete work= 1_15

time taken by pawan to complete remain work=

2/3_15×2/3= 10 days

Answered by nipunikaa2
1

Answer:

10 days

Step-by-step explanation:

work done by Shanu in 1 day= 1/10

work done by pawan in 1 day= 1/15

now work done by both in one day = 1/10+1/15= 5/30 = 1/6

work done by both in 2 days = 1/6×2=1/3

now remain work = 1-1/3 = 2/3

now again time taken by pawan to do the work in one day 1/15

time taken by pawan to complete work= 1_15

time taken by pawan to complete remain work=

2/3_15×2/3= 10 days

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