shape of a garden is rectangular in the middle and
en circular at the ends as shown in the diagram Find
the area and the perimeter of
garden [Length of
rectangle is 20 (3.5 +3.5) metres.
Answers
Answer:
Area = 129.47 m2
Perimeter = 48 m
Step-by-step explanation:
Given-
7m as the breadth and the diameter of the semi-circles
Procedure-
Since, diameter of the semi-circle is 7m
Therefore, radius = 7/2 m = 3.5 m
Now, Length of the rectangle
= [20-(3.5+3.5)]m
= 20-7 m
= 13 m
Therefore, Area
= (length*breadth)
= 13*7 m2
= 91 m2
Area of the semi-circles
= 2*π*(r*r)/2 m2
= π*(r*r) m2
= 3.14* 3.5*3.5 m2
= 38.47 m2 (approx.)
Therefore, area of the garden
=(Area of both the semi-circles + Area of the rectangle)
=(38.47 + 91) m2
=129.47 m2
We know,
Perimeter of a semi-circle = πr+2r
Thus, perimeter of only the circular part= πr
Therefore, Perimeter of the 2 circular portions of the garden
=2*π*r
=22 m (approx)
Perimeter of the straight portions
= 2*length of the rectangle
= 2*13 m
= 26 m
Therefore, total perimeter of the garden
=(26+22)m
=48 m
Hope this helps you!!
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