Math, asked by Anonymous, 6 months ago

shape of a garden is rectangular in the middle and
en circular at the ends as shown in the diagram Find
the area and the perimeter of
garden [Length of
rectangle is 20 (3.5 +3.5) metres.

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Answers

Answered by PPramanik
1

Answer:

Area = 129.47 m2

Perimeter = 48 m

Step-by-step explanation:

Given-

7m as the breadth and the diameter of the semi-circles

Procedure-

Since, diameter of the semi-circle is 7m

Therefore, radius = 7/2 m = 3.5 m

Now, Length of the rectangle

= [20-(3.5+3.5)]m

= 20-7 m

= 13 m

Therefore, Area

= (length*breadth)

= 13*7 m2

= 91 m2

Area of the semi-circles

= 2*π*(r*r)/2 m2

= π*(r*r) m2

= 3.14* 3.5*3.5 m2

= 38.47 m2 (approx.)

Therefore, area of the garden

=(Area of both the semi-circles + Area of the rectangle)

=(38.47 + 91) m2

=129.47 m2

We know,

Perimeter of a semi-circle = πr+2r

Thus, perimeter of only the circular part= πr

Therefore, Perimeter of the 2 circular portions of the garden

=2*π*r

=22 m (approx)

Perimeter of the straight portions

= 2*length of the rectangle

= 2*13 m

= 26 m

Therefore, total perimeter of the garden

=(26+22)m

=48 m

Hope this helps you!!

Answered by chganesh2005
0

Answer:

Please friend Don't leave please

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