shape of solid iron rod is cylinder height is 11 cm & base diameter is 7 cm find toyal volume of 50 such rods
Answers
Answered by
23
Height of rod = 11 cm
Diameter = 7 cm
Radius = 7/2 cm
Volume of 1 rod = pi *r^2 *h
= 22*7*7*11/7*2*2
= 11*11*7/2
= 121*7/2
= 847/2 cm^3
Volume of 50 rods = 847* 50 /2
= 25*847
= 21175 cm^3
Diameter = 7 cm
Radius = 7/2 cm
Volume of 1 rod = pi *r^2 *h
= 22*7*7*11/7*2*2
= 11*11*7/2
= 121*7/2
= 847/2 cm^3
Volume of 50 rods = 847* 50 /2
= 25*847
= 21175 cm^3
Answered by
15
Volume of cylinder = Pi x r^2 x h
R=D/2 = 7/2
Hence Volume = 22/7 x (7/2)^2 x 11
= 22/7 x 49/4 x 11
= 847/2
Volume of 50 such rods = 847/2 x 50
= 847 x 25
= 21175
R=D/2 = 7/2
Hence Volume = 22/7 x (7/2)^2 x 11
= 22/7 x 49/4 x 11
= 847/2
Volume of 50 such rods = 847/2 x 50
= 847 x 25
= 21175
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