Math, asked by adityakothari38, 4 months ago

sharad covers two-third of a certain distance at at 4 km/h and remaining at 5 km/h . If he takes 42 minutes in all , what is the total distance .​

Answers

Answered by Abhinav77173
3

Answer:

3 km

Step-by-step explanation:

Let the distance = x km.

Sharad covers 2/3rd distance at 4km/hr.

= 4 km in 1 hr.

then, (2/3)*x km in = 2x/12 hr. = x/6 hr.

Rest 1/3rd distance at 5km/hr.

= 5km in 1hr.

then, (1/3)*x km in = x/15 hr.

Total time taken = 42/60 hr.

x/6 + x/15 = 7/10

(5x+2x)/30 = 7/10

7x/30 = 7/10

x = 3 km.

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