Question

shashank's age is 4 times of his younger brother's age . They differ by 12 years . Find their ages.​

Answer 1

Answer:

let be the age of shashanks brother be x.

Step-by-step explanation:

thus the age of shashank is 4x. according to conditions,. 4x-x=12. 3x=12. X=12/3. X=4. thus the age of you get brother is 4 years and shashanks aga is 4x= 4*4=16 years

Answer 2

Answer:

Age of shashank = 16 years

Age of brother = 4 years

Step-by-step explanation:

Given---->

---------

Shashank 's age is 4 times of his younger brother's age and they differ by 12 years

To find --->

-------------

Their ages

Solution--->

---------------

Let age of shashank be x years

and age of his younger brother be y years

ATQ

Shasank 's age = 4 (brother 's age )

=> x = 4 y ----------------(1)

ATQ

shashank's age - brother's age = 12

=> x - y = 12 -----------------(2)

Now we solve these equation by substitution method

So putting x = 4y in equation (2)

4y - y = 12

=> 3 y = 12

=> y = 12 / 3

=> y = 4

Now putting y = 4 in equaion (1)

x = 4 y

=> x = 4 (4)

=> x = 16

Age of shashank = x = 16 years

Age of brother = y = 4 years