Question

Shashank walks 12m north from his house and turns west to walk 35 m to reach his friend’s house. While returning, he walks diagonally from his house to reach back home. What distance did he walk while returning?​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

let;

take the 12m towards north as Base

i.e

$base = 12m$

Now,

take 35 m west as perpendicular

i.e

$perp = 35m$

Now, we have to find hypotenius

for which we use pythaghorus thoerm

i.e

$hyp = \sqrt{base ^{2} + perp^{2}}$

so putting the values in above equation i.e

$hyp = \sqrt{12 ^{2} + 35^{2} }$

$hyp = \sqrt{144 + 1225}$

$hyp = \sqrt{1369}$

$hyp = 37m$

So he cover 37m while returning through diagnol path

answer: 37m