shat that 12n can not end with digits 0 or 5 for any natural numbers n
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hey mate here is your answer 12 and has factors 2 and 6 but to end with digit 0 and 5 it should we have factors 2 and 5 so 12 n cannot end with digit 0 or 5 for any natural number N
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12n=(4×3)n
12 has two factors 4 and 3.we know that by fundamental theorem of arithmetic every composite number has unique prime factors
12has factors 4 and 3only now (12)n ends with 0.then it must have other prime factors.
12n never ends with zero Or 5
As per not getting 5
12n=6×2n
12 has two factors 2 and 6.we know that by fundamental theorem of arithmetic every composite number has unique prime factors
12has factors 2 and 6 only now (12)n ends with 0.then it must have other prime factors.
12n never ends with zero Or 5
12 has two factors 4 and 3.we know that by fundamental theorem of arithmetic every composite number has unique prime factors
12has factors 4 and 3only now (12)n ends with 0.then it must have other prime factors.
12n never ends with zero Or 5
As per not getting 5
12n=6×2n
12 has two factors 2 and 6.we know that by fundamental theorem of arithmetic every composite number has unique prime factors
12has factors 2 and 6 only now (12)n ends with 0.then it must have other prime factors.
12n never ends with zero Or 5
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