Question

shatabdi express starts from rest and attaina a velocity of 108km/h in 2min.if the acceleration is in uniform find displacement and acceleration​

Answer 1

Answer:

Shatabdi Express starting from rest attains is velocity of 108 km per hour in 2 minutes assuming the acceleration to be uniform find the value of acceleration the distance travelled by the train for attaining this velocity

Explanation:

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Answer 2

Answer :

• Acceleration of the train is 0.25m/s²
• Displacement of the train is 1.8km

According to the Question

It is given that ,

• Initial velocity ,u = 0m/s

• Final velocity ,v = 108×5/18 = 30m/s
• Time taken ,t = 2min = 2×60 = 120s

• we have to calculate the uniform acceleration of the train and displacement of the train .

• Firstly we calculate the uniform acceleration of the train .

Using Kinematics Equation a = v-u/t

Substitute the value we get

➾ a = 30-0/120

➾ a = 30/120

➾ a = 1/4

➾ a = 0.25m/s²

Hence, the acceleration of the train is 0.25m/s²

Now, calculating the displacement of the train .

Again using Kinematics Equation v² = u² + 2as

Putting all the values we get

➾ 30² = 0² + 2×0.25 × s

➾ 900 = 0 + 0.50 × s

➾ 900 = 0.50×s

➾ s = 900/0.50

➾ s = 1800m

➾ s = 1.8km

• Hence, the displacement of the train is 1.8 kilometres.