Geography, asked by felixqi411, 7 hours ago

Shaun's tent (shown below) is a triangular prism.

Find the surface area, including the floor, of his tent.

Answers

Answered by sk7018542
1

Answer:

Answer:

The surface area of the ten t including the floor is 52.8 m².

Step-by-step explanation:

We are given that,

Shaun's tent consists of 3 rectangles and 2 triangles.

1. The dimensions of the rectangles are 5 × 3 meters.

Since, Area of the rectangle = Length × Width

i.e. Area of 3 rectangles = 3 × Length × Width

i.e. Area of 3 rectangles = 3 × 5 × 3 = 45 m²

Thus, area of the 3 rectangles is 45 m².

2. The dimensions of the triangles are base= 3 meter and height= 2.6 meter

As, Area of the triangle = \frac{1}{2}\times Base\times Height

2

1

×Base×Height

i.e. Area of 2 triangles = 2\times \frac{1}{2}\times Base\times Height2×

2

1

×Base×Height

i.e. Area of 2 triangles = Base\times HeightBase×Height

i.e. Area of 2 triangles = 3\times 2.63×2.6

i.e. Area of 2 triangles = 7.8 m²

Thus, area of 2 triangles is 7.8 m².

So, the total surface area of the prism = Area of rectangles + Area of triangles

i.e. Total surface area = 45 + 7.8 = 52.8 m²

Hence, the surface area of the ten t including the floor is 52.8 m².

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