Question

Shaurya's age is three times his son's age. Five years ago, he was four times his son's age. Find the present age of Shaurya​

Answer 1

Answer:

Step-by-step explanation:

Let present age of the son is x years.

Then the age of the father is 3x years.

Then according to the problem we get,

3x−4=4(x−4)  

or, 4x−3x=16−4

x=12.

So the son's age is 12 years and that of the father is 12×3=36 years.