Shaw that tan 30⁰ = tan 60⁰ −tan 30⁰ ÷ 1+ tan 60⁰. tan 30⁰
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Step-by-step explanation:
tan 30⁰ = tan 60⁰ −tan 30⁰ ÷ 1+ tan 60⁰. tan 30⁰
1/√3=(√3)-(1/√3)÷1+(√3)×(1/√3)
1/√3=[(3-1)/√3]÷1+1
1/√3=(2/√3)×(1/2)
1/√3=1/√3
LHS=RHS
Hence proved
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