Question

She measured the angles of incidence for both the rays on the left side of the box to be 48.60. She knew the refractive index of the material 'X' inside the box was 1.5. What will be the approximate value of angle of refraction?
A. 450
B. 40°
C. 30°
D. 60°
(use the value: sin 48.6°= 0.75)​

Answer 1

Answer:

C. 30°

Explanation:

Answer 2

Given:

Angle of incidence = i = 48.60°

Refractive index of material 'X' inside box = 1.5

sin 48.6° = 0.75

To find:

Approximate value of angle of refraction = r

Step-by-step solution:

$n_{1}$ = refractive index of medium 1 (Here air) = 1

$n_{2}$ = refractive index of medium 2 (Here mat. X) = 1.5 -- (given)

Angle of refraction can be found with the help of Snell's law as follows-

$n_{1} sin(i)=n_{2} sin(r)$

∴ 1 * sin 48.6° = $n_{2}$ sin r

∴ 0.75 = 1.5 * sin r  (∵ sin 48.6° = 0.75 is given)

∴ sin r = 0.5

∴ r = 30°

Thus, angle of refraction = 30°

Answer:

The value of angle of refraction is 30°