Question

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Find the ratio in which the line segment joining the points (-3,10) and (6.-8) is divided by (-1,6)

Answer 1

Answer: 2:7

Step-by-step explanation:

Let the points be

A(-3,10) B(6,8) C(-1,6)

- we need to find the ratio between AC & CB

Let the ratio be K:1

Hence,

m1 = k and m2 = 1

x1 = -3 and y1 = 10

x2 = 6 and y2 = -8

& x = -1 and y = 6

Then use section formula :

X= (m1x2+m2x1)/(m1+m2)

-1 = (k•6+1•-3)/(k+1)

-1 = (6k-3)/(k+1)

-1(k+1)=6k-3

-k-1=6k-3

-k-6k=-3+1

-7k=-2

K=(-2)/(-7)

K=(2)/(7)

Hence the ratio is k:1

= (2)/(7) : 1

Multiple both sides by 7

= 7•(2)/(7) : 7•1

= 2:7

So, the ratio is 2:7

Answer 2

ur answer is attached mate...