Question

she wants her son work on land and grow different crops. she divides her land into equal parts by drawing the diagonal . If it's perimeter is 400 m and one of the length of the diagonal is 120 m . how much area of them will get for hs crop .​

Answer 1

Answer:

4800 m^2

Step-by-step explanation:

perimeter of Rhombus = 400 m,each side = 100 m.Using Pythagoras theorem,AO^2 = 100^2 - 80^2 = 10000-6400 = 3600AO = 60SO AC = 2(AO) =120Area of Rhombus = 1/2 * Product of diagonals = 1/2 * 160 * 120 = 9600 m^2The area that each of the children get = 9600/2 = 4800 m^2

hope it's help

mark as brainliest

Answer 2

Answer:

s = (a + b + c)/2 = (100 + 100 + 160)/2 = 180 m.

Therefore, Area of △ABD = root under (√s(s - a)(s - b)(s - c))

= root under (√180(180 - 100)(180 - 100)(180 - 160))

= root under (√180 x 80 x 80 x 20) = 4800 m2

Alternative method:

As the diagonals of rhombus bisect each other: Therefore

OD = 1/2.BD = 1/2 x 160 = 80 m

OC = 1/2.AC

In △OCD, we have,

CD2 = OC2 + OD2

1002 = OC2 + 802 ⇒ OC2 = 10000 - 6400

⇒ OC2 = 3600 ⇒ OC = 60 m

Therefore, area of △BCD = 1/2(BD x OC) = 1/2 x 160 x 60 = 4800 m2

∴ Each of them will get 4800 m2 of area for their crops.