Math, asked by babuephrane43, 2 months ago

sheela borrowed a sum of ₹10000 from leena at 7% per annum. find the interest and amount to be paid at the end of two years​

Answers

Answered by Sauron
87

Answer:

Sheela will return Rs. 11,400 including the interest of Rs. 1400 at the end of 2 years.

Step-by-step explanation:

Sheela borrowed = Rs. 10,000

Rate = 7%

Interest at the end of = 2 years

Amount and interest = ??

Using the formula:

\boxed{\sf{SI = \frac{Principal \times Rate \times Time}{100}}}

  • Principal = Rs. 10,000
  • Rate = 7%
  • Time = 2 years

\sf{\longrightarrow \: {SI = \dfrac{10000\times 7 \times 2}{100}}}

\sf{\longrightarrow \: {SI = \dfrac{100\times 14}{1}}}

\sf{\longrightarrow \: {SI =100 \times 14}}

\sf{\longrightarrow \: {SI =1400}}

Interest = Rs. 1400

_____________________

\boxed{\sf{Amount = Principal + Simple \: Interest}}

  • Principal = Rs. 10,000
  • Simple Interest = Rs. 1,400

\sf{\longrightarrow  \: Amount = 10000 + 1400}

\sf{\longrightarrow  \: Amount = 10000 + 1400}

\sf{\longrightarrow  \: Amount = 11400}

Therefore, Sheela will return Rs. 11,400 including the interest of Rs. 1400 at the end of 2 years.

Answered by BrainlyRish
75

Given :

  • Sheela borrowed a sum of ₹10000 [ Principal ]
  • Rate of Interest is 7 % [ Rate of Interest ]
  • Interest at the end of 2 yrs [ Time ]

Exigency To Find : Interest & Amount.

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀

⠀⠀━━ Finding Interest :

\dag\:\:\it{ As,\:We\:know\:that\::}\\

\qquad \dag\:\:\bigg\lgroup \sf{ Simple \:Interest \:\::  \dfrac{ P \times R \times T }{100}  }\bigg\rgroup \\\\

⠀⠀⠀⠀⠀Here , P is the Principal , R is the Rate of Interest & T is the Time .

⠀⠀⠀⠀⠀⠀\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\

\qquad  :\implies \sf Interest = \dfrac { 10,000 \times 7 \times 2 }{100} \\

\qquad  :\implies \sf Interest = \dfrac { 10,0\cancel {00} \times 7 \times 2 }{\cancel {100}} \\

\qquad  :\implies \sf Interest =  100 \times 7 \times 2  \\

\qquad  :\implies \sf Interest =  700 \times 2  \\

\qquad :\implies \frak{\underline{\purple{\:Interest = Rs.1400\:\: }} }\bigstar \\

Therefore,

⠀⠀⠀⠀⠀\therefore {\underline{ \mathrm {\:Interest \:is\:\bf{Rs. \:1400}}}}\\

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⠀⠀━━ Finding Amount :

\dag\:\:\it{ As,\:We\:know\:that\::}\\

\qquad \dag\:\:\bigg\lgroup \sf{ Amount \:\::  Interest + Principal }\bigg\rgroup \\\\

⠀⠀⠀⠀⠀Here , Interest is Rs. 1400 & Principal is Rs. 10,000

\qquad  :\implies \sf Amount = 1400 + 10,000 \\

\qquad :\implies \frak{\underline{\purple{\:Amount = Rs.11,400 \:}} }\bigstar \\

Therefore,

⠀⠀⠀⠀⠀\therefore {\underline{ \mathrm {\:Amount \:is\:\bf{Rs. \:11,400}}}}\\

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