Math, asked by ANMOL8391, 9 months ago

Sheela can choose to go for a party with Yogesh, Nikhilesh, Shashank,Amol Shainu, Vivek, Girish. She has 10 pairs of sandals and 17 differentdresses. In how many different ways she will go to the party if she has achoice of taking 5 of her friends. Also she likes 7 pair of sandals and 15dresses which she wants to wear for the party?​

Answers

Answered by kalaiarul
13

Answer:

2205

Step-by-step explanation:

No ways of choosing friends = 7C5

No of pair of sandals she like= 7

No of pair of dress she like = 15

= 7C5 ×7×15

→2205

Answered by AmoliAcharya
0

Given: Here we have given Sheela can choose to go for a party with Yogesh, Nikhilesh, Shashank,Amol Shainu, Vivek, Girish. She has 10 pairs of sandals and 17 differentdresses

To find: we have to find In how many different ways she will go to the party if she has achoice of taking 5 of her friends. Also she likes 7 pair of sandals and 15dresses which she wants to wear for the party?​

Solution:

Here we have the given,

No ways of choosing friends= \[{}^{7}{{C}_{5}}\]

No of pair of sandals she like= \[{}^{7}{{C}_{1}}\]

No of pair of dress she like = \[{}^{15}{{C}_{1}}\]

= \[{}^{7}{{C}_{5}}\] \times \[{}^{7}{{C}_{1}}\] \times \[{}^{15}{{C}_{1}}\] \\

= 2205

Final answer:

Hence the answer is 2205

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