Sheela had a tank whose circular base has an area of 24.64 m2. Height of the tank is 80 cm. Find the cost of getting the outer curved surface painted at the rate of 120 per sq m.
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Answer. ..
Let r be the radius of base and h be the height of the tank.Now, h = 80 cm = 80100 m = 0.8 mNow, area of circular base = 24.64 m2⇒πr2 = 24.64⇒227 × r2 = 24.64⇒r2 = 7.84⇒r= 2.8 mCSA = 2πrh = 2 × 227 ×2.8 × 0.8 = 44 × 0.4 × 0.8= 14.08 m2Now, cost of painting 1 m2 area = Rs 120So, cost of painting 14.08 m2 area = Rs 1689.60
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nikhilyadav1611:
nice answer
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24.64 m2=22/7 ×r2
(24.64×7)22=r2 and further on ull get the radius..
substitute radius and height in the formula to get csa of tank + the area of circular base
(ie. area to be painted= pie×r2 + csa of cylinder)
(24.64×7)22=r2 and further on ull get the radius..
substitute radius and height in the formula to get csa of tank + the area of circular base
(ie. area to be painted= pie×r2 + csa of cylinder)
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