Math, asked by vishalprasad059, 10 months ago

sheela has ₹ 48,324 in her bank account. she withdrawal ₹ 28,000 in the first time and ₹6,500 the second time in a day.How much money is left in her account?​

Answers

Answered by THEVIBHANSHU
2

Answer:

13,824 rs

Step-by-step explanation:

THE MONEY LEFT IN HER ACCOUNT

= TOTAL NO. OF MONEY - SUM OF MONEY SHE TAKED OUT BOTH DAYS

SO, TOTAL SUM OF MONEY ALREADY IN ACCOUNT

=48,324

SHE TAKES AMOUNT 1ST DAY= 28,000

SHE TAKES AMOUNT 2ND DAY = 6,500

SUM OF MONEY IN BOTH DAYS= 34,500

NOW,

MONEY LEFT IN HER ACCOUNT = 48,324-34,500

=13,824 rs

REGARDS@THANKS

BY-THEVIBHANSHU

pls mark MARK BRAINLIEST

Answered by nspvaishnavi
3

Answer:

Step-by-step explanation:

1) First add the withdrawals in a day  - First time + Second Time

   a. Money withdrawn in first time = 28,000

   b. Money withdrawn in second time = 6500

Therefore total money withdrawn = 28000 + 6500 = 34500

2) Next subtract the above money from the total money in the bank

   a. Total money in the bank = 48324

   b. Total money withdrawn in first time and second time = 34500

Therefore money left in the bank = 48324 - 34500 = Rs. 13824

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