Math, asked by patrasailabala1, 4 months ago

Sheela wants to fix ribbon along the border of a painting .I f the length and breadth of the painting are 36 cm 15 cm respectively , how much ribbon is required by sheela ?​

Answers

Answered by Anonymous
3

= 2(l+b)

= 2(36+15)

= 2(51)

= 102cm

Hope this'll help you.

Answered by siddhigupta0304
0
Perimeter of a rectangle= 2(l+b)
= 2(36+15)
= 2(51)
= 105.

Therefore, Sheela requires 102 cm of ribbon.
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