Question

Sheena got a salary hike of 20 percent for two consecutive years.If her salary was 30,000 two years back,What is her present salary?​

Answer 1

Concept:-

Here, Sheena's salary increased for two consecutive year in a sequence of 20% every year. If her two years back salary was ₹30,000. Find his present salary.

Given:-

• Hike in salary of Sheena is 20% every year.
• Two years back salary was ₹30,000.

To Find:-

• What is her present salary ?

Solution:-

Here, Let the one year back salary be ₹x.

So, According to the question,

$\sf{\implies 30,000 + 30,000 \times \dfrac{20}{100} = x}$

$\sf{\implies 30,000 + 6,000 = x}$

$\sf{\implies 36,000 = x}$

Hence, The one year back salary was ₹36,000.

Now, Let present salary be ₹y.

So, According to the question,

$\sf{\implies 36,000 + 36,000 \times \dfrac{20}{100} = y}$

$\sf{\implies 36,000 + 7,200 = y}$

$\sf{\implies 43,200 = y}$

Hence, The present salary of Sheena is ₹43,200.

Answer 2

Answer:

Concept:-

Here, Sheena's salary increased for two consecutive year in a sequence of 20% every year. If her two years back salary was ₹30,000. Find his present salary.

Given:-

Hike in salary of Sheena is 20% every year.

Two years back salary was ₹30,000.

To Find:-

What is her present salary ?

Solution:-

Here, Let the one year back salary be ₹x.

So, According to the question,

\sf{\implies 30,000 + 30,000 \times \dfrac{20}{100} = x}⟹30,000+30,000×

100

20

=x

\sf{\implies 30,000 + 6,000 = x}⟹30,000+6,000=x

\sf{\implies 36,000 = x}⟹36,000=x

Hence, The one year back salary was ₹36,000.

Now, Let present salary be ₹y.

So, According to the question,

\sf{\implies 36,000 + 36,000 \times \dfrac{20}{100} = y}⟹36,000+36,000×

100

20

=y

\sf{\implies 36,000 + 7,200 = y}⟹36,000+7,200=y

\sf{\implies 43,200 = y}⟹43,200=y

Hence, The present salary of Sheena is ₹43,200.