Question

Sheena is 8 years younger than her brother shppiu. Find, the sum of their ages is 48 years

Answer 1

✬ Sheena's age = 20 Years ✬

✬ Brother's age = 28 Years ✬

Step-by-step explanation:

Given:

• Sheena is 8 years younger than her brother.
• Sum of Sheena's and brother's age is 48 years.

To Find:

• What is their ages ?

Solution: Let brother's age be x years. Therefore,

➛ Sheena's age = 8 years younger than x

➛ Sheena's age = (x – 8) years

A/q

• Sum of their ages is 48 years.

$\implies{\rm }$ (Sheena + Brother) age = 48

$\implies{\rm }$ (x – 8 + x) = 48

$\implies{\rm }$ 2x – 8 = 48

$\implies{\rm }$ 2x = 48 + 8

$\implies{\rm }$ 2x = 56

$\implies{\rm }$ x = 56/2

$\implies{\rm }$ x = 28

Hence,

➪ Brother's age is x = 28 years.

➪ Sheena's age = (x–8) = (28–8) = 20 years.

Answer 2

Given that ,

• Sheena is 8 years younger than her brother shppiu

• The sum of their ages is 48 years

Let ,

• The present age of Sheena's brother be " x "

• Then , the present age of Sheena will be x + 8

According to the question ,

x + x + 8 = 48

2x = 40

x = 20

$\therefore \sf \underline{The \: present \: age \: of \: Sheena \: and \: her \: brother \: will \: be \: 28 \: years \: and \: 20 \: years }$