Question

sheena's mother age is 4 times as old as sheena. After 5 years her mother will be 3 times as old as she will be then. Find their present ages.​

Answer 1

$\bf{\huge{\underline{\boxed{\tt{\red{Answer:}}}}}}$

Given :-

• Sheena's mother age is 4 times as old as Sheena.
• After 5 years Sheena's mother will be 3 times as old as Sheena will be after 5 years.

To find :-

• Present age of Sheena
• Present age of Sheena's mother

Sóĺúťíóń :-

Let the present age of Sheena be x years

As per the first condition,

• Sheena's mother age is 4 times as old as Sheena.

•°• Mother's present age = 4x years

As per the second condition,

• After 5 years her mother will be 3 times as old as she will be then,

Sheena's age after 5 years = x + 5 years

Mother's age after 5 years = 4x + 5 years

Mother is 3 times as old as Sheena.

Let's represent it mathematically and solve the equation formed.

4x + 5 = 3 ( x + 5 )

4x + 5 = 3x + 15

Transport the terms,

4x - 3x = 15 - 5

x = 10

•°• Present age of Sheena = x = 10 years

Substitute the value of x in Mother's age.

Mother's age = 4x = 4 × 10 = 40 years.

•°•Present ages of Sheena and Mother are 10 years and 40 years, respectively.

$\bf{\huge{\underline{\boxed{\tt{\red{Verification:}}}}}}$

For first case :-

• Sheena's mother age is 4 times as old as Sheena.

Sheena = 10 years

Mother = 40 years

Age of Sheena's mother is 4 times the age of Sheena.

x = 4x

40 = 4 × 10

40 = 40

LHS = RHS.

For second case :-

• After 5 years her mother will be 3 times as old as Sheena will be after 5 years

After 5 years,

Sheena's age = 10 + 5 = 15 years

Mother's age = 40 + 5 = 45 years

Age of mother is 3 times the age of Sheena.

4x + 5 = 3 ( x + 5)

4 × 10 + 5 = 3 ( 10 + 5)

40 + 5 = 30 + 15

45 = 45

LHS = RHS.

Hence verified.

Answer 2

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