Math, asked by manishaghatole22089, 9 months ago

sheepherd has 200 sheep with him. find the number of sheeps with him after 3 years if the increase in number of sheeps is 8% every year​

Answers

Answered by latha6028
1

200+8÷100×200

=200+16

216

216+216×8÷100

=233

233+233×8÷100

=251

Answered by mdtariq786
1

Step-by-step explanation:

Shepherd has 200 sheeps

he increase 8% every year

After 3 year?

=200*8%

=200*8/100

=16

Now, Shepherd has 200+16=216 sheeps from first year.

2nd year,

=216*8%

=216*8/100

=1728/100

=17.28

After 2 years Shepherd has 216+18=234 sheeps

3rd year,

=234*8%

=234*8/100

=1872/100

=18.72

After 3 years Shepherd has 234+19=253 sheeps.

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