Math, asked by randomrager, 2 months ago

Sheeza has a piece of canvas whose area is 553 m² She uses it to make a corucal tent with a base diameter of 14 m Assuming all stitching margins and wastage incurred while cutting amounts 3 m Find the volume of the air happed in the conical tent.

pls pls..i need it a bit urgently​

Answers

Answered by StormEyes
13

\Large Solution!!

radius=\frac{14}{2}=7\:m

Let slant height=l m

Let height=h m

Area of canvas=Curved surface area of conical tent+wastage

553m²=CSA of conical tent+3m²

CSA of conical tent=553m²-3m²

CSA of conical tent=550m²

550=πrl

550=\frac{22}{\cancel 7}\times \cancel 7\times l

550=22l

l=\frac{550}{22}

l=25m

l²=h²+r²

25²=h²+7²

h²=25²-7²

h²=(25-7)(25+7)

h²=(18)(32)

h²=576

h=\sqrt{576}

h=24m

Volume\:of\:air\:in\:the\:tent=\frac{1}{3}\pi r^{2}h

Volume\:of\:air\:in\:the\:tent=\frac{1}{3}\times \frac{22}{7}\times 7^{2}\times 24 m³

Volume\:of\:air\:in\:the\:tent=\frac{1}{3}\times \frac{22}{7}\times 49\times 24 m³

Volume of air in the tent=22×7×8 m³

\boxed{\bigstar Volume\:of\:air\:in\:the\:tent=1232m^{3}}

Answered by yadavmamta7121
0

Step-by-step explanation:

Solution!!

radius=\frac{14}{2}=7\:mradius=

2

14

=7m

Let slant height=l m

Let height=h m

Area of canvas=Curved surface area of conical tent+wastage

553m²=CSA of conical tent+3m²

CSA of conical tent=553m²-3m²

CSA of conical tent=550m²

550=πrl

550=\frac{22}{\cancel 7}\times \cancel 7\times l550=

7

22

×

7

×l

550=22l

l=\frac{550}{22}l=

22

550

l=25m

l²=h²+r²

25²=h²+7²

h²=25²-7²

h²=(25-7)(25+7)

h²=(18)(32)

h²=576

h=\sqrt{576}h=

576

h=24m

Volume\:of\:air\:in\:the\:tent=\frac{1}{3}\pi r^{2}hVolumeofairinthetent=

3

1

πr

2

h

Volume\:of\:air\:in\:the\:tent=\frac{1}{3}\times \frac{22}{7}\times 7^{2}\times 24 m³Volumeofairinthetent=

3

1

×

7

22

×7

2

×24m³

Volume\:of\:air\:in\:the\:tent=\frac{1}{3}\times \frac{22}{7}\times 49\times 24 m³Volumeofairinthetent=

3

1

×

7

22

×49×24m³

Volume of air in the tent=22×7×8 m³

\boxed{\bigstar Volume\:of\:air\:in\:the\:tent=1232m^{3}}

★Volumeofairinthetent=1232m

3. please help new here

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