Sheila is a wildlife biologist. At the beginning of each year, she tracks the wild turkey and white-tail deer population in the game reserve where she works. At the first year Sheila counted 12 wild turkeys, and their number increases by approximately 40% each year. At the first year Sheila counted 181818 white-tail deer, and their number increases by 10 additional deer per year. What is the first year in which Sheila counts more turkeys than deer?
Answers
Answered by
49
Question needs to be corrected :
It will be 18 white-tail deer instead of 181818.
Solution :
• In 1st year :
Number of wild turkeys = 12
Number of white-tail deer = 18
• In 2nd year :
Number of wild turkeys
= (1 + 40%) × 12
= (1 + 40/100) × 12
= 140/100 × 12
= 16.8
Number of white-tail deer
= 18 + 10
= 28
• In 3rd year :
Number of wild turkeys
= (1 + 40%) × 16.8
= (1 + 40/100) × 16.8
= 140/100 × 16.8
= 23.52
Number of white-tail deer
= 28 + 10
= 38
• In 4th year :
Number of wild turkeys
= (1 + 40%) × 23.52
= (1 + 40/100) × 23.52
= 140/100 × 23.52
= 32.928
Number of white-tail deer
= 38 + 10
= 48
• In 5th year :
Number of wild turkeys
= (1 + 40%) × 32.928
= (1 + 40/100) × 32.928
= 140/100 × 32.928
= 46.0992
Number of white-tail deer
= 48 + 10
= 58
• In 6th year :
Number of wild turkeys
= (1 + 40%) × 46.0992
= (1 + 40/100) × 46.0992
= 140/100 × 46.0992
= 64.53888
Number of white-tail deer
= 58 + 10
= 68
• in 7th year :
Number of wild turkeys
= (1 + 40%) × 64.53888
= (1 + 40/100) × 64.53888
= 140/100 × 64.53888
= 90.354432
Number of white-tail deer
= 68 + 10
= 78
In the case of 7th year, we see that the number of wild turkeys is counted more than the number of white-tail deer.
It will be 18 white-tail deer instead of 181818.
Solution :
• In 1st year :
Number of wild turkeys = 12
Number of white-tail deer = 18
• In 2nd year :
Number of wild turkeys
= (1 + 40%) × 12
= (1 + 40/100) × 12
= 140/100 × 12
= 16.8
Number of white-tail deer
= 18 + 10
= 28
• In 3rd year :
Number of wild turkeys
= (1 + 40%) × 16.8
= (1 + 40/100) × 16.8
= 140/100 × 16.8
= 23.52
Number of white-tail deer
= 28 + 10
= 38
• In 4th year :
Number of wild turkeys
= (1 + 40%) × 23.52
= (1 + 40/100) × 23.52
= 140/100 × 23.52
= 32.928
Number of white-tail deer
= 38 + 10
= 48
• In 5th year :
Number of wild turkeys
= (1 + 40%) × 32.928
= (1 + 40/100) × 32.928
= 140/100 × 32.928
= 46.0992
Number of white-tail deer
= 48 + 10
= 58
• In 6th year :
Number of wild turkeys
= (1 + 40%) × 46.0992
= (1 + 40/100) × 46.0992
= 140/100 × 46.0992
= 64.53888
Number of white-tail deer
= 58 + 10
= 68
• in 7th year :
Number of wild turkeys
= (1 + 40%) × 64.53888
= (1 + 40/100) × 64.53888
= 140/100 × 64.53888
= 90.354432
Number of white-tail deer
= 68 + 10
= 78
In the case of 7th year, we see that the number of wild turkeys is counted more than the number of white-tail deer.
Answered by
7
Answer:
7 years
Step-by-step explanation:
i had the khan academy problem 2
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