Question

Sheila is now 15 year older than her younger brother sanjay. ten years from now sheila will be twice as old as sanjay .find the present age of each of them.

Answer 1

Let sanjay's age be x
Then, Sheila's age = x + 15
10 years later,
Sanjay's age = 10x
And, Sheila's age = 10(x + 15)
=10x + 150
So,
2 * 10x = 10x + 150
20x = 10x + 150
20x - 10x = 150
10x = 150
X = 150/10
X = 15
So,
Sanjay's age = 15
And, Sheila's age = 15 + 15 = 30
Hope it helps...!!!

Answer 2

Answer:

Sanjay = 5yrs

Shiela = 20 yrs

Step-by-step explanation:

  Let the Present age of Sanjay (in Years ) = x

     Therefore , Present age of Sheila = x+15

     After 10 years ,

       Shielas age =  x+15+10

                         = x+25

       sanjay's age = x+10

According to question ,

               x+25 = 2(x+10)

               x+25 = 2x + 20

             25 = 2x + 20 - x

             25 = x+20

             25 - 20 =x

             5 =x

or x=5

Hence Present age of Sanjay = 5 years

and Present age of Shiela = x+15

                                      = 5+15

                                       = 20 years

Hope this helps you!!